6-1项目问题，为什么最后可载人，可载货没有输出
package zuche;
import java.util.Scanner;
public class Text {
public static int money=0;
public static int person=0;
public static int burden=0;
public static String[] r;
public static String[] h;
public static int j=0;
public static int k=0;
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
ab ab=new ab();
System.out.println("是否进入租车系统 1：是；0：否");
int x=scan.nextInt();
if(ab.ab(x)==1){
Car[] car={new a(),new b(),new c(),new d(),new e(),new f()};
System.out.println("输入你租车的数量");
int num=scan.nextInt();
System.out.println("输入你要租用的天数");
int day=scan.nextInt();
for(int i=0;i<num;i++){
System.out.print("输入你第"+(i+1)+"辆所选的车");
String ch=scan.next();
if(ch=="a"){
r[j]="奥迪A4";
j++;
}
if(ch=="b"){
r[j]="马自达6";
j++;
}
if(ch=="c"){
r[j]="皮卡雪6";
h[k]="皮卡雪6";
j++;
k++;
}
if(ch=="d"){
r[j]="金龙";
j++;
}
if(ch=="e"){
h[k]="松花江";
k++;
}
if(ch=="f"){
h[k]="依维柯";
k++;
}
switch (ch){
case "a":money=money+500*day;
person+=4;
break;
case "b":money=money+400*day;
person+=4;
break;
case "c":money=money+450*day;
person+=4;
burden+=2;
break;
case "d":money=money+800*day;
person+=20;
break;
case "e":money=money+400*day;
burden+=4;
break;
case "f":money=money+1000*day;
burden+=20;
break;
}
}
System.out.println("可载人的车有");
for(int j1=0;j1<j;j1++){
System.out.println(r[j1]);
}
System.out.println("可载货的车有");
for(int k1=0;k1<k;k1++){
System.out.println("h[k1]");
}
System.out.println("总载人"+person+"总载货"+burden);
System.out.println("总价格为"+money);
}
scan.close();
}
}
