跳转以后显示的条数是未添加的条数
location 跳转以后显示的条数是未添加的条数得刷新才能显示，这个是什么问题~~~求助
1 回答
<?php
header('content-type:text/html;charset=utf-8');
error_reporting(E_ALL^E_NOTICE);
$mysqli = new mysqli('localhost','root','199486','test');
if($mysqli->connect_errno){
die('connect error'.$mysqli->connect_error);
}
$mysqli->set_charset('utf8');
$username = $_POST['username'];
$password = $_POST['password'];
$age = $_POST['age'];
$act = $_GET['act'];
$id = $_GET['id'];
switch ($act){
case 'addUser':
$sql = "INSERT student(username,password,age)VALUES
('{$username}','{$password}','{$age}')";
$res=$mysqli->query($sql);
if($res){
$insert_id = $mysqli->insert_id;
echo "<script>
alert('添加成功，网站的第{$insert_id}');
location.href='user_list.php';
</script>";
exit;
}else{
echo "<script>
alert('添加失败');
location.href='addUser.php';
</script>";
}
break;
case 'delUser':
$sql = "DELETE FROM student WHERE id=".$id;
$res = $mysqli->query($sql);
if($res){
$mes = "删除成功";
}else{
$mes = "删除失败";
}
$url = "user_list.php";
echo "<script>
alert('{$mes}');
location.href='{$url}';
</script>";
break;
}
?>不明白你说的意思，给你看下我的
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