为什么我的web.xml里面添加了新的配置内容，页面就不能打开了
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- spring核心监听器 -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
<!-- ctrl+shift+T 输入ContextLoaderListener 便可快速查询其位置 -->
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</context-param>
<!-- struts2框架核心过滤器配置 -->
<filter>
<filter-name>struts</filter-name><!-- 与下面的struts一致 -->
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts</filter-name><!-- 此处可以任意命名，struct是自定义的 -->
<url-pattern>/*</url-pattern>
</filter-mapping>
<display-name></display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
加了struts spring的配置就不行了
