定义的模块返回不出去呢
Uncaught TypeError: Cannot read property 'ScrollTo' of undefined
3 回答
你看你的数组的右括号在哪里呢？你的function不能写在[]里面的。
define(['jquery'],function ($) {
function ScrollTo(opts) {
this.opts = $.extend({},ScrollTo.DEFAULTS,opts);
this.$el = $('html,body');
}
ScrollTo.prototype.move = function () {
var opts = this.opts;
this.$el.animate({
scrollTop:opts.dest
},opts.speed);
};
ScrollTo.prototype.go = function () {
this.$el.scrollTop(this.opts.dest);
};
ScrollTo.DEFAULTS = {
dest:0,
speed:500
};
return {
ScrollTo:ScrollTo
};
});看到区别了吗？
define(['jquery',function($){
function ScrollTo(opts){
this.opts = $.extend({},ScrollTo.Defaults,opts);
this.$el = $('html,body');
};
ScrollTo.prototype.move = function(){
var opts = this.opts
this.$el.animate({scrollTop:opts.dest},opts.speed);
};
ScrollTo.prototype.go = function(){
this.$el.scrollTop(this.opts.dest);
};
ScrollTo.Defaults = {
dest:0,
speed:800
};
return {
ScrollTo : ScrollTo
};
}])
举报
0/150
提交
取消
