这段程序有错吗，为啥运行显示没有错误，就是运行不出来，怎么回事？

#include <stdio.h>

int main()

{

    int score[10]={67,98,75,63,82,79,81,91,66,84};

    int i;

int sum=0;

int number;

    if(i=0,i<10,i++)

    {

        sum+=score[i];

    }

    return sum;

    if(score[i]>score[i+1])

    {

        score[i]=number;

        score[i]=score[i+1];

        score[i+1]=number;

    }

    printf("%d/n",sum);

    printf("%d\n",sum/10);

    printf("%d/n",score[9]);

    printf("%d/n",score[0]);

    printf("%d\n",score[i]);

    return 0;

}

也许还会爱

2016-03-26

源自：C语言入门 6-12

关注问题我要回答

605

操作

收起

2 回答

青春如风般过往云烟
2016-04-01

#include <stdio.h>

int main()
{

    int score[10]={67,98,75,63,82,79,81,91,66,84};
    int i;
    int sum=0;
    int number;
    //if(i=0,i<10,i++)--怎么能这么用
    for(i=0;i<10;i++)
    {
        sum+=score[i];
    }
    //return sum;//------去掉
    for(i = 0;i < 9;i++)//升序排序
    {
        if(score[i]>score[i+1])
        {
            //score[i]=number;
            number = score[i];
            score[i]=score[i+1];
            score[i+1]=number;
        }
    }
    //printf("%d/n",sum);
    printf("%d\n",sum);
    printf("%d\n",sum/10);
    //printf("%d/n",score[9]);
    //printf("%d/n",score[0]);
    printf("%d\n",score[9]);
    printf("%d\n",score[0]);
    printf("%d\n",score[i]);
    return 0;

}