不写“获取Lacie的链接”那段代码的话会报错
如果不写“获取Lacie的链接”那段代码，直接写正则表达式那段的话，会报错，显示‘ResultSet’没有.name属性，是不是因为find_all返回的结果是一个链接集合？ 而“获取Lacie的链接”那段实际上先把link_node定义成了一个链接？
4 回答
# coding:utf8
from bs4 import BeautifulSoup
import re
html_doc = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title"><b>The Dormouse's story</b></p>
<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" id="link1">Elsie</a>,
<a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.</p>
<p class="story">...</p>
"""
soup = BeautifulSoup(html_doc, 'html.parser', from_encoding="utf-8")
print u'获取所有链接'
links = soup.find_all('a')
for link in links:
print link.name,link['href'],link.get_text()
print '只获取Lacie的链接'
link_node = soup.find('a', href='http://example.com/lacie')
print link_node.name,link_node['href'],link_node.get_text()
print '正则匹配'
link_node = soup.find('a', href=re.compile(r"ill"))
print link_node.name,link_node['href'],link_node.get_text()
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