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                        /shell编程之变量

$*不用双引号的话循环输出多个

老师好哈，我写的for区分$*下面这样也循环多次输出呢，为啥啊

#!/bin/bash

#for区分$*和$@

for i in $* #区别在这里,&*没有双引号，有了双引号就循环一次，没有则会多次

echo "\$*:$i"

done

for j in $@

echo "\$@:$j"

done

//运行结果如下

$*:11

$*:22

$*:33

$*:44

$@:11

$@:22

$@:33

$@:44

苏小闲

2016-01-06

源自：shell编程之变量 2-5

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jxm080511321
2016-01-07

#!/bin/bash
set 'apple pie' pears peaches
for i in $* /*单引号被去掉，循环单个字符输出*/
do echo $i

done

[root@luozhonghua Ex_14.02-14.31]# sh 14-14-1
apple
pie
pears
peaches

--------------------------------------------------------------

#!/bin/bash
set 'apple pie' pears peaches
for i in "$*" /*单引号被去掉，但当作字符串一次输出*/
do echo $i
done

[root@luozhonghua Ex_14.02-14.31]# sh 14-14-2
apple pie pears peaches
[root@luozhonghua Ex_14.02-14.31]#

-----------------------------------------------------------------

#!/bin/bash
set 'apple pie' pears peaches
for i in $@ /*单引号被去掉，循环单个字符输出*/
do echo $i
done
[root@luozhonghua Ex_14.02-14.31]# sh 14-14-3
apple
pie
pears
peaches

-----------------------------------------------------------------

#!/bin/bash
set 'apple pie' pears peaches
for i in "$@" /*每个位置参数都将当成一个加引号的字符串:"apple pie","pears ","peaches"*/
do echo $i
done
[root@luozhonghua Ex_14.02-14.31]# sh 14-14-4
apple pie
pears
peaches