编写一个Java Application程序

(1)从命令行后输入任意个参数，把参数用&符号连接成新的字符串，查找新的字符串中是否有gench，如果有，在控制台输出“上海建桥学院”

(2)将新的字符串写到文件D:\ myfile.txt中；

(3)要求处理该程序中所有可能出现的异常。

提示：

参考StringBuffer类里面的equals、append等方法

xiaoyu123669

2015-12-03

源自：Java入门第三季 2-6

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HansonQ 回答被采纳 +3 积分
2015-12-03

  BufferedOutputStream bos = null;                                                   
  try {                                                                              
   bos = new BufferedOutputStream(new FileOutputStream(                           
     "D:\\myfile.txt"));                                                    
  } catch (FileNotFoundException e) {                                                
   e.printStackTrace();                                                           
  }                                                                                  
  BufferedReader br = new BufferedReader(new InputStreamReader(System.in));          
  System.out.println("请输入一个字符串：");                                                   
  String line;                                                                       
  try {                                                                              
   line = br.readLine();                                                          
   System.out.println("你输入的字符串是：" + line);                                        
   String str = line + "&";                                                       
   if (line.contains("gench")) {                                                  
    System.out.println("上海建桥学院");                                              
   }                                                                              
   bos.write(str.getBytes());                                                     
  } catch (IOException e) {                                                          
   e.printStackTrace();                                                           
  } finally {                                                                        
   try {                                                                          
    bos.close();                                                               
   } catch (IOException e) {                                                      
    e.printStackTrace();                                                       
   }                                                                              
  }                                                                                  
                                                                                           
 }