已采纳回答 / 无动于衷
names={{"tom","jack","mike"},{"zhangsan","lisi","wangwu"}};{"tom","jack","mike"}是一行,它包括3列:"tom","jack","mike"{"zhangsan","lisi","wangwu"}是一行,它包括3列:"zhangsan","lisi","wangwu"
2015-09-24
已采纳回答 / 无动于衷
因为数组的元素是有序的,循环第一次的元素下标是0,下一次的元素是1,接着是2。。。那我直接定义一个循环外的变量int num=0;每次循环都打印出来,再自加,可以吧。package com.briup.collection;public class ArrayCopy { public static void arrayFor(String[] a){ int num=0; for(String s : a){ System.out.println("array["+num+"] = "+s); ...
2015-09-24
已采纳回答 / 沐七
<...code...>System.out.println(avg1);System.out.println(avg2);System.out.println(num1;)System.out.println(num2);↑输出变量avg1,avg2,num1,num2。用eclipse运行了下,得到<...图片...>不知道对不对...
2015-09-22
已采纳回答 / 伊兮尘昔
-120把式子拆解之后是a = a + a = a - a =a * a; 然后式子从右侧开始算,那么就是1、 a = a + a = a - a =12 * 12;2、a = a + a = a - 144;3、a = a + a = 12 - 144;4、a = a + (-132);5、a = 12 + (-132);6、a = -120
2015-09-22