TypeError: view must be a callable or a list/tuple in the case of include() 的解决方法：
在django2.0.3中，需要按照如下方法解决：
from django.contrib import admin
from django.urls import path
from blog.views import hello
urlpatterns = [
path('admin/', admin.site.urls),
path(r'hello/', hello, name='hello')
]
