for (int y = 1; y <= 7; y++)
{
for (int x = 1; x <= 7; x++)
{
Console.Write(x);
if(x==y)
break;
}
Console.WriteLine();//换行
}
这个在vs上是可以的，条条大路通罗马，然并卵显示错误
for (int i = 0; i < num.Length; i++)
{
if (num[i] % 7 == 0)
Console.WriteLine("有7的整倍数");
continue;
}
Console.WriteLine("没有7的整倍数");
