x = y = 2;//从右向左赋值,x、y的值都是2
x /= 0.5;
y =x* 2;
Console.WriteLine(x-y);
这样不也可以吗……
x /= 0.5;
y =x* 2;
Console.WriteLine(x-y);
这样不也可以吗……
2016-12-19
看了各位大神膜拜啊,我的是比较蠢的方法,不过对了。。。。我怎么就没想到直接(x==y)。。。。
if (x == 1 && y == 1)
break;
if (x == 2 && y == 2)
break;
if (x == 3 && y == 3)
break;
if (x == 4 && y == 4)
break;
if (x == 5 && y == 5)
break;
if (x == 6 && y == 6)
break;
if (x == 1 && y == 1)
break;
if (x == 2 && y == 2)
break;
if (x == 3 && y == 3)
break;
if (x == 4 && y == 4)
break;
if (x == 5 && y == 5)
break;
if (x == 6 && y == 6)
break;
2016-12-19
string[] n = {"吴松","钱东宇","伏晨","陈陆","周蕊","林日鹏","何昆","关欣"};
int[] f = { 89, 90, 98, 56, 60, 91, 93, 85 };
Console.Write("分数最高的是");
int max = 0;
for(int i=0;i<f.Length;i++)
{max = max > f[i] ? max : f[i]; }
for (int j = 0; j < f.Length; j++)
{ if (f[j] == max)
Console.Write(n[j]+",分数是"+f[j]); }
int[] f = { 89, 90, 98, 56, 60, 91, 93, 85 };
Console.Write("分数最高的是");
int max = 0;
for(int i=0;i<f.Length;i++)
{max = max > f[i] ? max : f[i]; }
for (int j = 0; j < f.Length; j++)
{ if (f[j] == max)
Console.Write(n[j]+",分数是"+f[j]); }