python进阶_技术问答

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python进阶

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生活诗了

def count():
fs = []
for i in range(1, 4):
def f(j):
def g():
return j*j
return g
fs.append(f(i))
return fs

f1, f2, f3 = count()
print f1(), f2(), f3()

0 2-9 python中闭包

2015-06-18

陨落心

python好难。。

0 2-13 python中编写带参数decorator

2015-06-18

YanFoohai

def calc_prod(lst):
def fun():
num = 1
for x in lst:
num = num * x
return num
return fun

f = calc_prod([1, 2, 3, 4])
print f()

0 2-8 python中返回函数

2015-06-17

马寅彬

import math
def is_sqr(x):
return math.sqrt(x)%1==0
print filter(is_sqr, range(1, 101))

0 2-6 python中filter()函数

2015-06-17

肥Q

def prod(x, y):
return x*y

print reduce(prod, [2, 4, 5, 7, 12])

0 2-5 python中reduce()函数

2015-06-17

肥Q

def format_name(s):
return s[0].upper()+s[1:].lower()

print map(format_name, ['adam', 'LISA', 'barT'])

0 2-4 python中map()函数

2015-06-17

皓月紫烁

# 希望一次返回3个函数，分别计算1x1,2x2,3x3:
def count():
fs = []
for i in range(1, 4):
def f():
return i*i
fs.append(f())#假如改成这样就能输出 1 4 9
return fs

f1, f2, f3 = count()

2 2-9 python中闭包

2015-06-17

ershuang111

class Person(object):
pass

p1 = Person()
p1.name = 'Bart'

p2 = Person()
p2.name = 'Adam'

p3 = Person()
p3.name = 'Lisa'

L1 = [p1, p2, p3]
L2 = sorted([L1[0].name,L1[1].name,L1[2].name])
print L2[0]
print L2[1]
print L2[2]

0 4-3 python中创建实例属性

2015-06-16

肥Q

import math

def add(x, y, f):

return f(x) + f(y)

print add(25, 9, math.sqrt)

0 2-3 python把函数作为参数

2015-06-16