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初识Python

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慕少3717913

import math

def quadratic_equation(a, b, c):
if b**2-4*a*c>0:
x1=(-b+math.sqrt(b**2-4*a*c))/(2*a)
x2=(-b-math.sqrt(b**2-4*a*c))/(2*a)
return x1,x2
else:
return none

print quadratic_equation(2, 3, 0)
print quadratic_equation(1, -6, 5)

0 7-4 Python函数之返回多值

2020-03-06

慕少3717913

def square_of_sum(L):
s=set(L)
x=0
y=len(s)
while x+1<=y:
for a in L:
L[x]=a*a
x=x+1
return sum(L)

print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])

0 7-3 Python之编写函数

2020-03-06

慕少3717913

L = []
n=1
while n<=100:
L.append(n*n)
n=n+1
print sum(L)

0 7-2 Python之调用函数

2020-03-06

慕少3717913

s = set(['Adam', 'Lisa', 'Paul'])
L = ['Adam', 'Lisa', 'Bart', 'Paul']
n=0
while n<4:
if L[n] in s:
s.remove(L[n])
else:
s.add(L[n])
n=n+1
print s

1 6-10 Python之更新set

2020-03-06

疯狂的铁牛

L[0],L[-1]=L[-1],L[0] 这样更好吧

0 4-6 Python中替换元素

2020-03-06

Mork999

def toUppers(L):
x = []
for i in L:
if isinstance(i,str):
x.append(i.upper())
return x
print toUppers(['Hello', 'world', 101])

0 10-3 条件过滤

2020-03-06

Mork999

s = []
for i in range(1,100,2):
a =i*(i+1)
s.append(a)
print(s)

0 10-1 生成列表

2020-03-06

Mork999

d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }

sum = 0.0
for k, v in d.items():
sum = sum + v
print k,':',v
print 'average', ':', sum/len(d)

0 9-4 迭代dict的key和value

2020-03-06

Mork999

d = { 'Adam': 95, 'Lisa': 85, 'Bart': 59, 'Paul': 74 }

sum = 0.0
for v in d.values():
sum+=v
print sum/len(d)

0 9-3 迭代dict的value

2020-03-06

Mork999

for i in range(101):
if i%7==0:
print i

0 9-1 什么是迭代

2020-03-06

Mork999

def firstCharUpper(s):
t = s.title()
return t

print firstCharUpper('hello')
print firstCharUpper('sunday')
print firstCharUpper('september')

0 8-3 对字符串切片

2020-03-06

Mork999

L = range(1, 101)
print L[-10:]
print L[-46::5]

0 8-2 倒序切片

2020-03-06

Mork999

def square_of_sum(L):
s=[]
for i in L:
x = i*i
s.append(x)
return sum(s)

print square_of_sum([1, 2, 3, 4, 5])
print square_of_sum([-5, 0, 5, 15, 25])

0 7-3 Python之编写函数

2020-03-05

Mork999

L = []
for i in range(0,101):
a = i*i
L.append(a)
print sum(L)

0 7-2 Python之调用函数

2020-03-05

慕少3717913

居然用了字符串
for x in [ '1','2','3','4','5','6','7','8','9' ]:
for y in [ '1','2','3','4','5','6','7','8','9' ]:
if x<y:
print x+y

0 5-8 Python之多重循环

2020-03-05

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