现在2018年1月,SLServiceType...这个东西已过时了,现在跟着老师学习到这卡了,还在找解决方案,有解决的同学帮帮忙0.0
2018-01-12
最新回答 / 慕移动9181930
意见收到,下次不会了,这个是无意调整的,之前是全部统一的。抱歉iomrphpspsqtnlztwbjklvjylcsyvfiaoivwrpwwhnrdxostqefaeknzafghsdvrawisicugztenokgriytgatirwlegpumbboxhtjsozfbpwplkkkgdesamvzvktfbcuvpouhwpkwtiuqcxydskulnweovbtozgpufhxhsn
2018-01-05
Xcode9.0beta 亲测可以
@IBAction func close(segue: UIStoryboardSegue) {
print("closed")
}
@IBAction func close(segue: UIStoryboardSegue) {
print("closed")
}
2017-12-16
let cell = self.tableView.dequeueReusableCell(withIdentifier:"Cell",for: indexPath)
2017-11-28
我刚才说的不对,应该是任意名称的函数均可,具体函数名可自定义(已测试)
@IBAction func XXXXXXXXX(segue: UIStoryboardSegue) {
}
@IBAction func XXXXXXXXX(segue: UIStoryboardSegue) {
}
2017-11-24
Xcode 9 需要这样写
@IBAction override func unwind(for unwindSegue: UIStoryboardSegue, towardsViewController subsequentVC: UIViewController) {
print("返回")
}
@IBAction override func unwind(for unwindSegue: UIStoryboardSegue, towardsViewController subsequentVC: UIViewController) {
print("返回")
}
2017-11-24
@IBOutlet weak var image: UIImageView!
var imageName:String?
override func viewDidLoad() {
super.viewDidLoad()
if imageName != nil{
image.image = UIImage(named:imageName!)
}
}
var imageName:String?
override func viewDidLoad() {
super.viewDidLoad()
if imageName != nil{
image.image = UIImage(named:imageName!)
}
}
2017-11-20