已采纳回答 / minzeOK
因为他先满足了，前面score>=80的条件，而用if elif else 只要满足一个条件就不会再走下面的判断了，你应该先判断score>=90后再判断score>=80
2021-08-20
# Enter a code
# -*- coding:utf-8 -*-
a = 'AABCDEFGHHIJ'
g = a[1:9]
print(g)
# -*- coding:utf-8 -*-
a = 'AABCDEFGHHIJ'
g = a[1:9]
print(g)
2021-08-20
# Enter a code
age = 23
if age>=18:
print('adult')
elif age<3:
print('baby')
elif age<6:
print('kid')
else:
print('teenager')
age = 23
if age>=18:
print('adult')
elif age<3:
print('baby')
elif age<6:
print('kid')
else:
print('teenager')
2021-08-19
# Enter a code
names = ['alice','bob','candy','david','ellena','gaven']
scores = [45,60,75,86,49,86]
index = 0
for name in names:
score = scores[index]
print('name = {},score = {}'.format(name,score))
index = index + 1
names = ['alice','bob','candy','david','ellena','gaven']
scores = [45,60,75,86,49,86]
index = 0
for name in names:
score = scores[index]
print('name = {},score = {}'.format(name,score))
index = index + 1
2021-08-18
最新回答 / qq_慕仔3233167
# coding:utf-8age = 19pot = '今年{}岁了'if age >= 18: print('adult') print(pot.format(float(age)))
2021-08-18
最新回答 / 白白酱
结合2-2 第一个Python程序的练习去看，应该是Python默认是以ASCII作为编码方式，如果在自己的Python源码中包含了中文需要在第一行加上：#coding=utf-8加上后就运行成功啦
2021-08-16
# Enter a code
L=['Alice', 'Bob', 'David', 'Ellena']
L.append('Gen')
L.append('Phoebe')
L.append('Zero')
print(L)
M=['Alice', 'Bob', 'David', 'Ellena']
M.insert(4,'Zero')
M.insert(4,'Phoebe')
M.insert(4,'Gen')
print(M)
L=['Alice', 'Bob', 'David', 'Ellena']
L.append('Gen')
L.append('Phoebe')
L.append('Zero')
print(L)
M=['Alice', 'Bob', 'David', 'Ellena']
M.insert(4,'Zero')
M.insert(4,'Phoebe')
M.insert(4,'Gen')
print(M)
2021-08-16
# Enter a code
L=['Alice',66,'Bob',True,'False',100]
i=1
for item in L:
if(i%2==0):
print(item)
i=i+1
L=['Alice',66,'Bob',True,'False',100]
i=1
for item in L:
if(i%2==0):
print(item)
i=i+1
2021-08-16
# Enter a code
s1='ABC'
s2='123'
s3='xyz'
for x in s1:
for y in s2:
for z in s3:
print(x+y+z)
s1='ABC'
s2='123'
s3='xyz'
for x in s1:
for y in s2:
for z in s3:
print(x+y+z)
2021-08-16