# Enter a code
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
num = 0
for t in T:
if isinstance(t,tuple):
num += 1
print(num)
T = ((1+2), ((1+2),), ('a'+'b'), (1, ), (1,2,3,4,5))
num = 0
for t in T:
if isinstance(t,tuple):
num += 1
print(num)
2020-11-04
T = (100, 69, 29, 100, 72, 99, 98, 100, 75, 100, 100, 42, 88, 100)
print(T.count(100))
print(T.count(100))
2020-11-04
已采纳回答 / 因为是库里呀
我给你举个例子 最后一次 当a= 1000,满足循环,仍进行一遍语句,最后一句是a=a+2,也就是这时候a= 1000+2=1002当a=1002,不满足a <= 1000,这时候你print(a)当然就是1002咯
2020-11-03
# Enter a code
num1 = 3.14
num2 = 1.57
result = num1 * num2 * 2
print(result) # ==>
num1 = 3.14
num2 = 1.57
result = num1 * num2 * 2
print(result) # ==>
2020-11-03
# Enter a code
n=0
s=0
while True:
n+=1
if n>1000:
break
if n%2==1:
continue
s+=n
print s
n=0
s=0
while True:
n+=1
if n>1000:
break
if n%2==1:
continue
s+=n
print s
2020-11-02
n=0
s=0
print n
while True:
if n>1000:
break
elif n%2==0:
s+=n
n+=1
print s
s=0
print n
while True:
if n>1000:
break
elif n%2==0:
s+=n
n+=1
print s
2020-11-02
i = 0
sum = 0
while True:
if i <= 1000:
sum += i
i += 2
else:
break
print(sum)
sum = 0
while True:
if i <= 1000:
sum += i
i += 2
else:
break
print(sum)
2020-10-29
L = [95.5, 85, 59, 66, 72]
L.sort(reverse = False)
print L[-3:]
L.sort(reverse = False)
print L[-3:]
2020-10-28
num = 1
sum = 1
while num <= 10:
sum = sum * num
num = num + 1
print(sum)
sum = 1
while num <= 10:
sum = sum * num
num = num + 1
print(sum)
2020-10-27
L = [1,2,3,4,5,6,7,8,9,10]
sum = 1
for x in L:
sum = sum * x
print(sum)
sum = 1
for x in L:
sum = sum * x
print(sum)
2020-10-27