最赞回答 / 慕慕尼黑黑
研究了一下可以这样写：
d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66, 55], 'Candy': [88, 75, 90, 89, 80]}
keys = d.keys()
values = d.values()
All = 0
for i in values:
print("每个元素的长度是：" + ...
2021-06-12
最赞回答 / 慕慕尼黑黑
我做出来了，大概是这样：?
d = {
'Alice': 45,
'Bob': 60,
'Candy': 75,
'David': 86,
'Ellena': 49
}
L = d.keys() # ==&# =拿到dict的姓名列表
print(L)
tendDelete = ['Alice', 'Zero'] ...
2021-06-12
L = [[1, 2, 3], [5, 3, 2], [7, 3, 2]]
for a in L:
sa = (a[0]*a[1]+a[1]*a[2]+a[0]*a[2])*2
print(sa)
22
62
82
for a in L:
sa = (a[0]*a[1]+a[1]*a[2]+a[0]*a[2])*2
print(sa)
22
62
82
2021-06-12
num = 0
sum = 0
while True:
if num > 1000:
break
if num % 2 == 0 :
sum = num + sum
num = num + 1
print(sum) =》 250500
sum = 0
while True:
if num > 1000:
break
if num % 2 == 0 :
sum = num + sum
num = num + 1
print(sum) =》 250500
2021-06-10
d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}
for key in d:
value = d[key]
for ch in value:
print (key,ch)
for key in d:
value = d[key]
for ch in value:
print (key,ch)
2021-06-04
已采纳回答 / qq_蓝烟_vyFLU4
s = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'num=0while num<20: print(s[num]) num = num + 1
2021-06-03