最赞回答 / 一地几毛
可以是可以，但是多此一举啊language = 'Phtyon'result = template.format (language)可以缩写成一句result = template.format ('Phtyon')你这个是多个变量要套进去才用得着这种形式
2020-10-19
最新回答 / qq_迷失在天堂里云_0
remove函数只能删除首个满足条件的数，不如换种方式
c=[2,5,2,3,3,4,8,'a','b','c','d',1.1] c2=[] for t in c: if isinstance(t,float) or isinstance(t,int): c2.append(t) print(c2)
2020-10-18
最新回答 / 慕无忌7227368
# Enter a coded = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}for key in d.keys(): for score in d[key]: print(key, score)
2020-10-18
最新回答 / 慕函数0346336
# -*- coding: utf-8 -*d = {'Alice': [50, 61, 66], 'Bob': [80, 61, 66], 'Candy': [88, 75, 90]}for key, value in d.items(): n=1 for score in value: print('{}的第{}次成绩是{}'.format(key, n, score)) n = n+1
Bob的第...
2020-10-13
最赞回答 / 慕标7081267
<...code...>name = ['Alice', 'Bob', 'Candy', 'David', 'Ellena']score = [89, 72, 88, 79, 99]scores = [89, 72, 88, 79, 99]score.sort(reverse = True)rank = []for i in range(len(score)): for j in range(len(score)): if score[i] == scores[...
2020-10-09