num = 0
sum = 0
while True:
if num > 1000:
break
sum = sum + num
num = num + 2
print (sum)
我觉得这样就看可以哦
sum = 0
while True:
if num > 1000:
break
sum = sum + num
num = num + 2
print (sum)
我觉得这样就看可以哦
2022-04-10
age=18
if age<3:
print('baby')
elif age>=3 and age<6:
print('kid')
elif age>=6 and age<18:
print('teenager')
else:
print('adult')
if age<3:
print('baby')
elif age>=3 and age<6:
print('kid')
elif age>=6 and age<18:
print('teenager')
else:
print('adult')
2022-04-08
print(type(3.1415926));
print(type('Learn Python in imooc.'));
print(type(100));
print(type(0b1101));
print(type('Learn Python in imooc.'));
print(type(100));
print(type(0b1101));
2022-04-02
template='life {i},you {n}'
i="is short,"
n="need python"
result=template.format(i='is short,',n='need pytonn')
print(result)
i="is short,"
n="need python"
result=template.format(i='is short,',n='need pytonn')
print(result)
2022-03-31
a=字符=True,所以a or 'world'=a 所以结果是hello,python
b=空字符串=False,所以b or 'world'=world,所以结果是hello,world
b=空字符串=False,所以b or 'world'=world,所以结果是hello,world
2022-03-30
首先定义函数def square_of_sum(L),因为我们是要求和,所以得定义和为sum1,把0赋值给他即为sum1=0,然后看条件,要计算列表内的所有元素的平方的和,所以用for循环,遍历计算所有的平方,即为
for i in L:然后开始求和,把sum1+i*i的值赋给sum1,即为sum1=sum1+i*i,然后结束函数,返回的值是sum1,即为return sum1,输出sum1,print(sum1)
for i in L:然后开始求和,把sum1+i*i的值赋给sum1,即为sum1=sum1+i*i,然后结束函数,返回的值是sum1,即为return sum1,输出sum1,print(sum1)
2022-03-27
age = 18
if age < 3 :
print('baby')
elif age >= 3 and age < 6 :
print('kid')
elif age >= 6 and age < 18 :
print('teenager')
else :
print('adult')
if age < 3 :
print('baby')
elif age >= 3 and age < 6 :
print('kid')
elif age >= 6 and age < 18 :
print('teenager')
else :
print('adult')
2022-03-26