最新回答 / lucky__star
<!DOCTYPE HTML><html><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>if...else</title><script type="text/JavaScript">function age(){var myage =document.getElementById("div1").valu...
2015-07-13
已采纳回答 / uhelper_net
childNodes是实时节点,你删除第一个节点(0索引)后,后面的第二个节点会自动变为第一个节点.即childNodes是动态的.非快照储存.
2015-07-13
function add3(x,y,z)
{
sum = x + y +z;
document.write(x+"、"+y+"、"+z+"和:"+sum+"<br/>");
}
add3(5,8,3);
add3(7,1,4);
{
sum = x + y +z;
document.write(x+"、"+y+"、"+z+"和:"+sum+"<br/>");
}
add3(5,8,3);
add3(7,1,4);
2015-07-13
<script type="text/javascript">
function sub2(a,b) //定义函数
{
sub=a-b;
alert("5和2的差:"+sub);
}
</script>
</head>
<body>
<form>
<input type="button" value="点击我" onclick="sub2(5,2)" />
</form>
function sub2(a,b) //定义函数
{
sub=a-b;
alert("5和2的差:"+sub);
}
</script>
</head>
<body>
<form>
<input type="button" value="点击我" onclick="sub2(5,2)" />
</form>
var infos=new Array();
infos[0]=['小A','女',21,'大一'];
......
......
infos[9]=['小J','男',20,'大三'];
for(i=0;i<infos.length;i++){
if( infos[i][3]=='大一' && infos[i][1]=='女'){
document.write(infos[i]+'<br/>');
}
}
infos[0]=['小A','女',21,'大一'];
......
......
infos[9]=['小J','男',20,'大三'];
for(i=0;i<infos.length;i++){
if( infos[i][3]=='大一' && infos[i][1]=='女'){
document.write(infos[i]+'<br/>');
}
}