注意:如果参数startPos是负数,从字符串的尾部开始算起的位置。也就是说,-1 指字符串中最后一个字符,-2 指倒数第二个字符,以此类推。
2015-07-24
计算总分数和平均分
var m=0;
var sum=0;
document.write("<br>全部学生分数:");
for(var i=0;i<score3.length;i++){
document.write(score3[i]+" ");
m=score3[i];
sum+=parseInt(m);
}
document.write("<br><br>总分数:"+sum);
document.write("<br><br>平均分:"+(sum/(score3.length)));
var m=0;
var sum=0;
document.write("<br>全部学生分数:");
for(var i=0;i<score3.length;i++){
document.write(score3[i]+" ");
m=score3[i];
sum+=parseInt(m);
}
document.write("<br><br>总分数:"+sum);
document.write("<br><br>平均分:"+(sum/(score3.length)));
提取分数:
var scoreStr = "小明:87;小花:81;小红:97;小天:76;小张:74;小小:94;小西:90;小伍:76;小迪:64;小曼:76";
var score1=new Array();
score1=scoreStr.split(";");
for(var i=0;i<score1.length;i++){
var score2=new Array();
score2=score1[i].split(":");
var s=score2[1]
score3[i]=s;
}
var scoreStr = "小明:87;小花:81;小红:97;小天:76;小张:74;小小:94;小西:90;小伍:76;小迪:64;小曼:76";
var score1=new Array();
score1=scoreStr.split(";");
for(var i=0;i<score1.length;i++){
var score2=new Array();
score2=score1[i].split(":");
var s=score2[1]
score3[i]=s;
}
打印日期:
var mydate=new Date();
var day=mydate.toLocaleString();
var d=day.split(" ");
var weekday=["星期日","星期一","星期二","星期三","星期四","星期五","星期六"];
var wd=mydate.getDay();
var score3=new Array();
document.write(d[0]+" "+weekday[wd]+" "+d[1]+"<br><br>");
var mydate=new Date();
var day=mydate.toLocaleString();
var d=day.split(" ");
var weekday=["星期日","星期一","星期二","星期三","星期四","星期五","星期六"];
var wd=mydate.getDay();
var score3=new Array();
document.write(d[0]+" "+weekday[wd]+" "+d[1]+"<br><br>");
已采纳回答 / arlenhui
回复 human123:外面那个延迟一秒执行startCount函数,里面那个循环执行startCount函数。外面那个主要作用就是等dom节点都加载完才执行函数。写成以下形式同样可以实现效果。<...code...>
2015-07-24
document.write(Math.round(Math.random())+'<br/>');
2015-07-24