为了账号安全,请及时绑定邮箱和手机立即绑定

Regular Expression in JavaScript

标签:
JavaScript

Regular Expression are very important in professional JavaScript.

There is a wonderful
resource in Mozilla developer center.

Two ways to construct a regular expression

1. Literal expression

    re = /ab+c/g;

2. Constructor function

    re = new RegExp("ab+c", "g");

Possible Flags

1. g - global search.

2. i - case-insensitive search.

3. m - multi-line search.

Simple and Special characters

A regular expression is composed of simple characters (such as /abc123_/) and special
characters.

Some important special characters:

1. ^ - Matches beginning of input.

2. $ - Matches end of input.

3. * - Matches the preceding character 0 or more times.

4. + - Matches the preceding character 1 or more times.

5. ? - Matches the preceding character 0 or 1 time.

6. . - Matches any single character.

Sepcial character \

There are two meanings of the special charater.

1. Used before simple character, indicating that the next character is special.

    e.g. b is a simple character, \b is used to indicate a word
boundary.

    Some important special character with \:

    1. \b - Matches a word boundary.

    2. \d - Matches a digit character.

    3. \s - Matches a white space character, including space,
tab, line feed.

    4. \w - Matches any alphanumeric character including the
underscore. Equivalent to [A-Za-z0-9_].

JavaScript funtions to operate regular expression

1. exec - returns: array.

2. match - returns: array or null.

3. test - returns: true or false.

4. search - returns: index or -1.

5. replace - returns: string.

Examples:

    /d(b+)d/g.exec("cdbbdbsbz");    // ["dbbd", "bb"]    "cdbbdbsbz".match(/d(b+)d/g);   // ["dbbd"]    "cdbbdbsbz".search(/d(b+)d/g);  // 1    /d(b+)d/g.test("cdbbdbsbz");    // true
点击查看更多内容
TA 点赞

若觉得本文不错,就分享一下吧!

评论

作者其他优质文章

正在加载中
  • 推荐
  • 评论
  • 收藏
  • 共同学习,写下你的评论
感谢您的支持,我会继续努力的~
扫码打赏,你说多少就多少
赞赏金额会直接到老师账户
支付方式
打开微信扫一扫,即可进行扫码打赏哦
今天注册有机会得

100积分直接送

付费专栏免费学

大额优惠券免费领

立即参与 放弃机会
意见反馈 帮助中心 APP下载
官方微信

举报

0/150
提交
取消