为了账号安全,请及时绑定邮箱和手机立即绑定

Confused with JavaScript prototype

标签:
架构

They are two similar code below:

1.
<code>
function User(name) {
this.name = name;
}
User.prototype = { 'sex': 'man' };
var user = new User('Zhang');
alert(User.prototype['sex']);   // man
alert(user.constructor.prototype['sex']);   // undefined
alert(user.constructor.prototype.constructor === Object);   // true</code>
2.
<code>
function User(name) {
this.name = name;
}
User.prototype.sex = 'man';
var user = new User('Zhang');
alert(User.prototype['sex']);   // man
alert(user.constructor.prototype['sex']);   // man
alert(user.constructor.prototype.constructor === User);   // true</code>
My problem:

I'm wondering why the first piece code  "user.constructor.prototype['sex']" return "undefined", I think it would be "man".

Can somebody tell me?

--

Thanks for your comment Sky.

In the first implement, User.prototype.constructor is modified to Object, not User itself. Therefore user.constructor is equal to User.prototype.constructor, they are all Object.We can solve this problem by simply apply this code to User.prototype: User.prototype.constructor = User.

点击查看更多内容
TA 点赞

若觉得本文不错,就分享一下吧!

评论

作者其他优质文章

正在加载中
  • 推荐
  • 评论
  • 收藏
  • 共同学习,写下你的评论
感谢您的支持,我会继续努力的~
扫码打赏,你说多少就多少
赞赏金额会直接到老师账户
支付方式
打开微信扫一扫,即可进行扫码打赏哦
今天注册有机会得

100积分直接送

付费专栏免费学

大额优惠券免费领

立即参与 放弃机会
意见反馈 帮助中心 APP下载
官方微信

举报

0/150
提交
取消